Advertisement



< Prev
Next >



C++ Conditional Operator





In this article, we are going to explain another operator provided by C++, conditional operator. It is also called ternary operator because it has three operands, such as




Syntax of conditional operator -


boolean-condition ? first expression : second expression;






Conditional operator example.


// Conditional Operator Example i C++

#include<iostream>

using namespace std;

int main()
{
int a=10, b=20;


int result =a>b ? 10 : 20;
cout<<"Result1 is : " <<result <<"\n";


result = a>b ? 10 : 100.50;
cout<<"Result2 is : " <<result <<"\n";


char ch = a>b ? 'y' : 'n';
cout<<"Result3 is : " <<ch <<"\n";


result = 100>=99 ? 100 : 99;
cout<<"Result4 is : " <<result <<"\n";

return 0;
}
Output
Result1 is 20
Result2 is 100
Result3 is n
Result4 is 100





  • The first expression of a conditional operator can be left blank

  • //Conditional Operator in C++
    
    #include<iostream>
    
    using namespace std;
    
    
    int main()
    {
    int a=10, b=20;
    
    int result = a>b ? 0 : 10;
    cout<< "Result1 is : " << result << "\n";
    
    char ch = a < b ? : 'n'; 	// Intentionally leaving the first expression 
    cout<< "Result2 is : " << ch << "\n";
    
    return 0;
    }


    Output-


    Result1 is 10
    Result2 is ☺

    In the last code, we have intentionally left out the first expression and the program has still compiled and executed successfully.




  • The second expression of a conditional operator cannot be left blank

  • #include<stdio.h>
    
    using namepsace std;
    
    int main()
    {
    result = 9<2 ? 9 : ;
    cout<< "Result2 is : " << result;
    }


    Output-


    func41.c:5:20: error: expected expression before ';' token
     result = 9<2 ? 9 : ;
                        ^

    In the last code, we have intentionally left out the second expression and the compiler has thrown an error, complaining that the second expression is expected before semicolon.


    Advertisement




  • An expression of a conditional operator can be a method call.
  • Any expression of a conditional operator could even be a call to a function but this function must return a value.

    #include<iostream>
    
    using namespace std;
    
    int main()
    {
    char fun(); // function prototype declaration
    
    char result = 100>99? fun() : 'n'; // Calling function fun() in the first expression 
    cout << "Result is " << result;
    
    return 0;
    }
    
    
    char fun()
    {
    return 'y';
    }
    


    Output-


    Result is y

    In the last code, the first expression of the conditional operator is a call to a function fun(), which has returned us a char y.



    Please share this article -





    < Prev
    Next >
    < Logical Operators in C++
    Scope Resolution Operator >



    Advertisement

    Please Subscribe

    Please subscribe to our social media channels for daily updates.


    Decodejava Facebook Page  DecodeJava Twitter Page Decodejava Google+ Page




    Advertisement

    Notifications



    Please check our latest addition

    PYTHON


    Advertisement